1 Answer

Rbaskam · Answer 1 · 2019-12-29T14:56:59+0000

If the function is defined for all
$x \\eq m$ , it means that
is a point who doesn't belong to the domain of the function.

Now, since your function is a ratio, you can't have zero denominator. So, if a point nullifies the denominator, it can't belong to the function domain.

In your case, the denominator is
x-2 , which is zero when

$x-2=0\iff x=2$

So, this function can't be evaluated at
x=2 , and in other words, the function is defined when
$x \\eq 2$ , so that's the value for
.

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