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Solve and write in interval notation. 4|x+4|+5>5

User Phil Gan
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4|x+4|+5>5\\\\4|x+4|>0\\\\|x+4|>0\\\\x+4>0 \vee x+4<0\\\\x>-4 \vee x<-4\\\\x\in(-\infty,-4)\cup(4,\infty)

User Vatsal Shukla
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Hi,


Solving:


4 |x + 4| + \\ot5 > \\ot5 \\ 4 |x + 4| > 0 \\ 4 |x + 4| = 0 \: \: \: \: \: | / 4 \\ |x + 4| = 0 \\ x + 4 = 0 \\ x = - 4 \\ x \in \: r \: \: \: \: \: ( - 4)

Answer: The inequality is true for any value of x, except when X = -4


Hope this helps.
r3t40
User Freonix
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