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Please answer with clear instructions so that i can apply this to other questions

Please answer with clear instructions so that i can apply this to other questions-example-1
User NeoNe
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1 Answer

17 votes
17 votes

Answer:

1 and - 1

Explanation:

The equation of a line passing through the origin is

y = mx ( m is the slope ( gradient ) )

y = x ← is in this form

with gradient m = 1

Parallel lines have equal gradients

Then the gradients of lines parallel to the given line is 1

Given a line with gradient m then the gradient of a line perpendicular to it is


m_(perpendicular) = -
(1)/(m) = -
(1)/(1) = - 1

Then the gradients of lines perpendicular to this line is - 1

User Nupac
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