Question

Considere os logaritmos log3=0,477 , log4=0,602 e / log5=0.699 logaritmos determine o valor de log5 12.

Escolha uma:
a. 1,544
b. 2,727
c. 1,455
d. 2,455
e. 1,953

Answer 1

Given that :

log3=0.477 , log4=0.602 and log5=0.699

Now , as you know that

`\log\text{MN}=\log M +\log N`

We have to find the value of

`\log_(5)12`

So,
`\log_(5)12`=
`(\log12)/( \log5)`

=
`(\log 4+\log 3)/(\log 5)\\`

Now Putting the values of log3, log4 and log5 in the above expression

`\log_(5)12=(0.477 +0.602)/(0.699)`

=1.0079/0.699

=1.5436..

=1.544 (approx)

So, the value of
`\log_(5)12` is 1.544(approx).