We were told that the distance
is directly proportional to the time
.
We write this mathematically as,
![D\propto T](https://img.qammunity.org/2019/formulas/mathematics/middle-school/7q4cpbdg85v9c26x2ahbmaqnwj7v964z4w.png)
We can now introduce our constant of variation and write the equation for the direct equation as;
![D=kT](https://img.qammunity.org/2019/formulas/mathematics/middle-school/6s5w8wbiq1nyetwpt5zm8q7q8i9kwlto5j.png)
where
is the constant of variation or constant of proportionality.
We substitute
and
, in to the equation of variation to obtain the constant of proportionality.
That is;
![20=k*15](https://img.qammunity.org/2019/formulas/mathematics/middle-school/hskfk7eex81pzxdnuny7335wbxgqvigqci.png)
This implies that,
![(20)/(15)=k](https://img.qammunity.org/2019/formulas/mathematics/middle-school/m9bc6xgcjix3mj05g8wfhsayt920evn8oc.png)
This simplifies to give us,
![k=(4)/(3)](https://img.qammunity.org/2019/formulas/mathematics/high-school/z0mbqu6th1nw7yomn137otdnb3x6n7gth3.png)
Now our equation of proportion becomes,
![D=(4)/(3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/7bsh0vzzsp2eb1xkgi6n2b210cxgi2xp88.png)
When T=20
![D=(4)/(3)*20](https://img.qammunity.org/2019/formulas/mathematics/middle-school/oh5g89u9kunh9wdk4dyyscfol97q1t7rx3.png)
![D=(80)/(3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/lt58ay13x3g4c5mo0qfemp5ek1nysbd6p5.png)
Writing this as a mixed number we obtain,
![D=26(2)/(3)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/wzu1ik3gkzvk32pck65hws4tyowta9fy6w.png)
This can also be rewritten as
correct to one decimal places.
Therefore the care covers
miles in
minutes.