Question

Approximately how many moles of chlorine make up 1.79 x 10^23 atoms of chlorine?

Answer 1

The answer of given question is 0.13 mol

Step-by-step explanation

1 mol of chlorine (Cl) contain =
`6.022^(23) N_(A) atoms` atoms (Avogadro Number)

So, we have to determine how many moles of Cl will be contain for
`0.79 * 10^(23) N_(A)`atoms.

As we know unit method

`6.022^(23) N_(A) = 1 mol of chlorine (Cl)`

`1 N_(A) atom = 1/6.022^(23) N_(A)`}

`0.79 * 10 ^(23) N_(A) = 1 mol * 0.79^(23) N_(A)/6.022^(23) N_(A)`

`0.79* 10 ^(23) N_(A) = 0.13 mol`

So, the answer is 0.13 mol