109,797 views
27 votes
27 votes
Given f(x)= 17- X? what is the average rate of change in f(x) over the interval [1, 5]?

-6
2
O
0 1
th

Given f(x)= 17- X? what is the average rate of change in f(x) over the interval [1, 5]? -6 2 O-example-1
User Paul Scheltema
by
3.1k points

2 Answers

22 votes
22 votes

Answer:

answer is -6

Explanation:

Here,

Let [1,5] be[a,b]

f(x)=17-x²

f(a)=17-a²=17-1²=17-1 = 16

f(b) = 17-b² = 17-5² = 17-25 = -8

now, using formula,

{f(b)-f(a)}/(b-a)

(-8-16)/(5-1)

-24/4

=-6

User Pavan Manjunath
by
2.7k points
26 votes
26 votes

Answer:

first option

Explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is


(f(b)-f(a))/(b-a)

Here [ a, b ] = [ 1, 5 ]

f(b) = f(5) = 17 - 5² = 17 - 25 = - 8

f(a) = f(1) = 17 - 1² = 17 - 1 = 16 , then

average rate of change =
(-8-16)/(5-1) =
(-24)/(4) = - 6

User Van Ng
by
3.1k points