Question

I need help with this calculus problem

Answer 1

First, find the value of g(x) at x=4: it's 3.

Next, use this result, 3, as the input to f(x): f(3) = 1

So f(g(4)) = 1.

Answer 2

This is a composite function, we apply the chain rule to differentiate,


`f(g(x))'=f'(g(x))* g'(x)`

At
`x=4`


`f(g(4))'=f'(g(4))* g'(4)`


`f(g(4))'=f'(3)* g'(4)`


`f(g(4))'=8*(-4)`


`f(g(4))'=-32`

The correct answer is option C