Question

Given f(x)= 17- X? what is the average rate of change in f(x) over the interval [1, 5]?

-6
2
O
0 1
th

Answer 1

answer is -6

Explanation:

Here,

Let [1,5] be[a,b]

f(x)=17-x²

f(a)=17-a²=17-1²=17-1 = 16

f(b) = 17-b² = 17-5² = 17-25 = -8

now, using formula,

{f(b)-f(a)}/(b-a)

(-8-16)/(5-1)

-24/4

=-6

Answer 2

first option

Explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

`(f(b)-f(a))/(b-a)`

Here [ a, b ] = [ 1, 5 ]

f(b) = f(5) = 17 - 5² = 17 - 25 = - 8

f(a) = f(1) = 17 - 1² = 17 - 1 = 16 , then

average rate of change =
`(-8-16)/(5-1)` =
`(-24)/(4)` = - 6