Question

HELP PLZ!!!

Frank solves the system of equations using the linear combination method.

2x+3y=−13x−5y=10
Which steps would allow him to eliminate the y terms in the system of equations?


Multiply 2x+3y=−1 by 5. Multiply 3x−5y=10 by 3. Add the resulting equations together.

Multiply 2x+3y=−1 by 2. Multiply 3x−5y=10 by 5. Add the resulting equations together.

Multiply 2x+3y=−1 by 3. Multiply 3x−5y=10 by 2. Add the resulting equations together.

Multiply 2x+3y=−1 by 3. Multiply 3x−5y=10 by 5. Add the resulting equations together.

Answer 1

Multiply 2x+3y=-1 by 5 and 3x-5y=10 by 3

3y*5=15y and -5y*3=-15y

Add -15y and 15y you have no y values left.

Your main focus is going to be on the y values. What can you multiply each y value by to get the same number so that when you add the positive and negative you get 0.

Answer 2

Multiply 2x+3y =-1 by 5. Multiply 3x-5y =-1 by 3. Add the resilting equations together.

Explanation:

As we need to eliminate the y term we could find the the common multiple of the y terms coefficients. As we can see the coefficients are 3 in the left member and -5 in the center member that means 15 will be the common multiple.

Then we multiply for the proper number to get the common multiple:

(2x+3y =-1)*5 ---> 10x +15y = - 5

(3x- 5y = 10)*3 ---> 30x - 15y = 10

Then by add term by term:

10x +15y = - 5

30x - 15y = 10

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40x + 0y = 5

Which solution will be x = 1/8