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What are the factors of x^4-81

User Enitihas
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1 Answer

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(x^2 - 9) and (x^2 + 9) are factors of x^4 - 81

We can verify this by multiplying them.

(x^2 - 9)(x^2 + 9)

x^4 + 9x^2 - 9x^2 - 81

x^4 - 81

When we have a binomial with two perfect squares, we can use this equation:


a^2 - b^2 = (a - b)(a + b)

User Phuc
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