Question

A liter of milk has mass of 1060 g and a 1,6 percent of mass in fat. Calculate the mass concentration of fat in g\L

Answer 1

The milk has a mass concentration of 17 g/l of fat.

Answer 2

The mass concentration of fat is 16.96
`(g)/(L)`

Step-by-step explanation:

The ratio between the mass of the solute and the mass of the resulting mixture is defined as percentage mass concentration (% m / m). This is:

`percentage mass of solute=(mass of solute)/(mass of solution) *100`

Then, in this cases the percent of mass in fat is:

`1,6=(x(g))/(1060g) *100`

Isolating the value of x is obtained:

`x=(1,6*1060)/(100) g`

x= 16.96 g

Considering that:

`mass concentration=(mass of solute(g))/(volume of solution(l))`

Then:

`mass concentration=(16.96 g)/(1 L)`

`mass concentration= 16.96 (g)/(L)`

So, the mass concentration of fat is 16.96
`(g)/(L)`