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5 votes
The distance and midpoint of (-5,5 ) (1,-2)

User Scrontch
by
5.9k points

1 Answer

4 votes

d = √85 , midpoint = (-2,
(3)/(2))

using the distance formula

d = √(1 + 5)² + (- 2 - 5)² = √(36 + 49) = √85

using the midpoint formula

midpoint = [
(1)/(2)(- 5 + 1 ),
(1)/(2) (5 - 2 )] = (-2,
(3)/(2))


User HenryM
by
6.0k points