41.8k views
4 votes
Calculate the height of a column of liquid benzene (d=0.879g/cm3), in meters, required to exert a pressure of 0.790 atm .

User Nikkya
by
6.9k points

1 Answer

5 votes

Answer:

9.29x10^-3m

Step-by-step explanation:

Step 1:

Data obtained from the question. This includes:

Density (ρ) = 0.879g/cm3

Pressure (P) = 0.790 atm

Height (h) =?

Step2:

Conversion to appropriate units. This is very vital in order to obtain the answer to the question in the desired unit.

For density:

1g/cm3 = 1x10^6g/m3

Therefore, 0.879g/cm3 = 0.879x1x10^6 = 879000g/m3

For pressure:

1 atm = 101325N/m2

Therefore, 0.790 atm = 0.790x101325 = 80046.75N/m2

Step 3:

Determination of the height

Pressure is related to height according to the following equation:

Pressure = Density x acceleration due to gravity x height

P = ρgh

P = 80046.75N/m2

ρ = 879000g/m3

g = 9.8m/s2

h =?

80046.75 = 879000 x 9.8 x h

Divide both side by 879000 x 9.8

h = 80046.75 / (879000 x 9.8)

h = 9.29x10^-3m

User Namig Hajiyev
by
7.4k points