Let consecutive integers a-1; a; a+1, then
a-1+a+a+1=21
3а=21
a=7.
7-1=6; 7+1=8.
Answer: 6; 7; 8.
Let the 3 numbers be x, x + 1 and x + 2, So:-
x + x + 1 + x + 2 = 21
3x = 21 - 3 = 18
x = 18/3 = 6
The 3 numbers are 6, 7 and 8 Answer
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