Question

I need help writing an equation of a graph in slope-intercept form & standard form. Plz (:

Answer 1

y = -
`(2)/(3)` x + 2 abd 2x + 3y = 6

The equation of a line in ' slope- intercept form ' is

y = mx + c → ( m is slope and c is the y- intercept)

The graph here slopes downwards from left to right thus slope is negative

m = -
`(2)/(3)` and c = 2

y = -
`(2)/(3)` x + 2 in slope- intercept form

the equation of a line in standard form is Ax + By = C

where A is a positive integer and B, C are integers

multiply all terms in the slope- intercept equation by 3

3y = - 2x + 6 → add 2x to both sides

2x + 3y = 6 in standard form