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A Federation starship (8.5 ✕ 106 kg) uses its tractor beam to pull a shuttlecraft (1.0 ✕ 104 kg) aboard from a distance of 14 km away. The tractor beam exerts a constant force of 4.0 ✕104 N on the shuttlecraft. Both spacecraft are initially at rest. How far does the starship move as it pulls the shuttlecraft aboard?

1 Answer

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Force applied by the beam is given as


F = 4 * 10^4 N

now the acceleration of starship is given as


a_1 = (F)/(m_1)


a_1 = (4 * 10^4)/(8.5 * 10^6) = 4.7 * 10^(-3) m/s^2

acceleration of space craft will be given as


a_2 = (F)/(m_2)


a_2 = (4 * 10^4)/(1 * 10^4) = 4 m/s^2

now the relative acceleration is given as


a = a_1 + a_2 = 4.0047 m/s^2

now the distance between them is d = 14000 m

now we can use kinematics to find the time to cover this distance


d = (1)/(2) at^2


14000 = (1)/(2)*4.0047* t^2


t = 83.62 s

now we have to find the distance moved by starship


d_1 = (1)/(2) a_1t^2


d_1 = (1)/(2)*0.0047* 83.62^2


d_1 = 16.4m

so it will move by 16.4 m distance

User Clayton Selby
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