2 Answers

Otuyh · Answer 1 · 2019-03-21T10:49:01+0000

we are given

y=sec(5x)

now, we can compare it with

$y=sec(\omega x)$

now, we can find omega

$\omega =5$

now, we can use formula

$\omega =2\pi f$

where f is frequency

$5 =2\pi f$

$f=(5)/(2\pi) hz$ .............Answer

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