Question

Each leg of an isosceles triangle is 4 meters longer than the base. the perimeter of the triangle is 26 meters. find the lengths of the side.

Answer 1

The length of the base is 6 and the length of each leg is 10.

In order to find this, we can start by making the length of the base x. Now we know that the legs are 4 longer we can mark them as x + 4. Since there are two of them, we can add x + x + 4 + x + 4 and set equal to 26 to find the value of x.

x + x + 4 + x + 4 = 26

3x + 8 = 26

3x = 18

x = 6

Now we can plug this in for our leg length as well to find that.

x + 4 = Leg

6 + 4 = Leg

10 = leg