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A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilometers/hour, the its kinetic energy will be joules. The braking at the faster speed is the breaking distance at the slower speed.

1 Answer

3 votes

ke prop to v^2


ke1/v1^2=ke2/v2^2


400/50x50=joules/100x100


400x2x2


1600j

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