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It took John 4 hours from his home to drive to Leakey, Tx.. On the way home his speed was reduced by 20 MPH due to heavy traffic and took 7 hours. How far is it to Leakey from John's home?

User Cgohlke
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1 Answer

4 votes

Let the speed at which John is going towards Leakey = x mph

Time taken to reach Leakey = 4 hours

Distance = speed * time

So let the distance of Leakey from John's house be 4x ............. (1)

Speed while returning was 20 mph less = (x-20)

Time taken was= 7 hours

distance = (x-20)*7 ................(2)

As the distance remains the same, equation 1 = equation 2


4x=7(x-20)


4x=7x-140


3x=140


x=(140)/(3)

So, the speed is
(140)/(3) mph

Distance = 4x

=
4*(140)/(3)= 186.667

Hence, the distance of Leakey from John's house is 186.667 miles.




User Gazihan Alankus
by
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