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If a person weighs 717 N on earth and 5320 N on the surface due to gravity on that planet? of a nearby planet, what is the acceleration

a. 83.6

b. 72.7

c. 63.2

d. 53.1

2 Answers

2 votes

The answer is B. You divide 717 by the acceleration by gravity of earth (9.8 m/s) and divide 5320 by your answer.

User Pibben
by
8.3k points
5 votes

Answer:


g'=72.7\ m/s^2

Step-by-step explanation:

It is given that,

Weight of the person on Earth, W = 717 N

Weight of a person is given by the following formula as :


W=mg

g is the acceleration due to gravity on earth


m=(W)/(g)


m=(717\ N)/(9.81\ m/s^2)

m = 73.08 kg

The mass of an object is the amount of matter contained in it. It is same everywhere.

Let W' is the weight of the person on the surface of a nearby planet, W' = 5320 N

g' is the acceleration due to gravity on that planet. So,


g'=(W')/(m)


g'=(5320\ N)/(73.08\ kg)


g'=72.79\ m/s^2

or


g'=72.7\ m/s^2

So, the acceleration due to gravity on that planet is
72.79\ m/s^2. So, the correct option is (b). Hence, this is the required solution.

User Pbrosset
by
8.2k points