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What is the slope of a line perpendicular to the line whose equation is x − 3 y = 12 x−3y=12.
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What is the slope of a line perpendicular to the line whose equation is x − 3 y = 12 x−3y=12.

User Zachariahyoung
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1 Answer

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The answer is -3
x-3y=12
-3y=-x+12
y=x/3 - 4

The slope of this line is 1/3 and -1/ (1/3) = -3
User Gigatron
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