(1)
we are given

we can find for y
multiply both sides by 6


we can see that y is directly proportional to x
so, option-D........Answer
(2)
y varies inversely with x
so, we can write it as

now, we are given
y=5 when x=2.5
so, we can plug it here

and then we can solve for k


now, we can plug back

we can plug x=20

.............Answer
(3)
we are given
The current, I, in a circuit varies inversely with the resistance, R
so, we can write it as

we have R=12 when I=3
so, we can plug it

now, we can solve for k


now, we can plug back

we can plug R=6

................Answer