Answer with explanation:
![\rightarrow √(128) \text{Lies between two square numbers} 121 \text{and} 144.\\\\121=11^2 \\\\ (11.1)^2=133.1](https://img.qammunity.org/2019/formulas/mathematics/middle-school/p8r8x9sh6a7ga4xdcrad2a9i94l6rgdm78.png)
So, √128 lies between 11.0 and 11.1.
Option A: →11.0 and 11.1
(B)→
√x lies between 10.1 and 10.2.
If →√x=10.1
Squaring both sides
x=102.01
and if , →√x=10.2
Squaring both sides
→x=104.04
Nearest Whole Number from 104.04 is 104.Why, 104 because the number √x is closer to 10.2 on the number line.
→The whole number best approximates the value of x is 104.
≡Option D:→ 104