17.1k views
2 votes
Factor the following expression

10X^5+5^3-14x^2-7
A (5X^3+7) (2X^2-1)
B (5x^4+7) (2x-1)
C(5x^3-7) (2x^2+1)
D(5x^4-7) (2x+1)

User JTejedor
by
7.0k points

2 Answers

3 votes

10X^5 + 5x^3 - 14x^2 - 7

= 5x^3(2x^2 + 1) - 7(2x^2 + 1)

= (5x^3 - 7)(2x^2 + 1) answer


User Ahmedshahriar
by
6.7k points
3 votes

Answer:

C.
(5x^3-7)(2x^2+1)

Explanation:

Given expression is,


10x^5+5x^3-14x^2-7


=10x^5-14x^2 + 5x^3 - 7 (By the commutative property)


=2x^2(5x^3-7)+5x^3-7 (Taking
2x^3 common from first two terms )


=(5x^3-7)(2x^2+1) (Taking
5x^3-7 common from both terms)


\implies 10x^5+5x^3-14x^2-7=(5x^3-7)(2x^2+1)

Hence, Option C is correct

User Joseph Katzman
by
6.8k points