Question

a ball is rolling down a hill at +1.0m/s the ball is uniformly accelerating at +4.9m/s^2 what will the balls velocity be 4.0 later

Answer 1

So velocity of ball after 4 sec will be 20.6 m/sec

Explanation:

We have given initial velocity of the ball u = 1 m/sec

Acceleration of the ball
`a=4.9m/sec^2`

We have to find velocity after 4 sec

So ti,e t = 4 sec

According to first equation of motion we know that v = u+at

So
`v=1+4.9* 4=20.6m/sec`

So velocity of ball after 4 sec will be 20.6 m/sec

Answer 2

we are given

initial velocity is +1.0 m/s

so,
`u=1.0m/s`

Let's assume final velocity as v

uniformly accelerating at +4.9m/s^2

so,
`a=4.9m/s^2`

time is 4 sec

so, t=4 s

now, we can use formula

`a=(v-u)/(t)`

we can plug values

`4.9=(v-1)/(4)`

`4.9*4=4*(v-1)/(4)`

`4.9*4=v-1`

`19.6=v-1`

`v=20.6m/s`...............Answer