50.1k views
0 votes
How to determine whether the given function is even,odd, or neither?
f(x) = x^3 + x^2 + 3

User Ursitesion
by
8.5k points

1 Answer

3 votes

f(x) = x^3 + x^2 + 3x^0 is neither even nor odd. Why? Because we have a mixture of even and odd powers of x here: x^3 (odd) and x^2 and x^0 (even).

Even functions: all component functions are even (e. g., x^2 and x^0).

Odd functions: all component functions are odd (e. g., x^5 and x^3.

Neither: There's a mixture of even ad odd functions.


Another way to test for even, odd or neither:

Even functions: f(-x) = f(x). Changing the sign of the input (x) doesn't change the sign of the output.

Odd functions: f(-x) = -f(x). Changing the sign of the input changes the sign of the output.


User Kaigorodov
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.