Question

In a classic carnival ride, patrons stand against the wall in a cylindrically shaped room. once the room gets spinning fast enough, the floor drops from the bottom of the room! friction between the walls of the room and the people on the ride make them the "stick" to the wall so they do not slide down. in one ride, the radius of the cylindrical room is r = 7.4 m and the room spins with a frequency of 21.1 revolutions per minute. 1) what is the speed of a person "stuck" to the wall?

Answer 1

The answer is 14.8 m/s.

Step-by-step explanation:

Substituting 22.1 revolutions for f, 6.4 meters for R in Relation between velocity and frequency of motion.

V = (2π) ( 22.1) (6.4)

= ( 2π) ( 22.1 rev/ min) ( 1min÷ 60 s )(6.4)

= 14.8 m/s.