Final answer:
The effective nuclear charge on boron's valence electrons would be different for the 2s electrons compared to the 2p electron due to the shape of their orbitals.
Step-by-step explanation:
In boron, the valence electrons are in the 2s and 2p orbitals. Based on the shape of these orbitals, we would predict that the effective nuclear charge on boron's valence electrons would be different for the 2s electrons compared to the 2p electron. The 2s electrons are closer to the nucleus and experience a stronger attractive force, resulting in a higher effective nuclear charge. In contrast, the 2p electron is shielded to some extent by the 2s electrons, leading to a lower effective nuclear charge.