Question

Please, please help me! I don't even know where to start with solving this...

sec(x)csc(x)+√2 csc(x)=0

Answer 1

Factorize the left hand side and equate the factors to zero.

Then, use the notation that : sec x = 1/cosx and csc x = 1/sinx

Result: x = ± π3 + 2πk , k∈Z