We have to choose 3 people at random and give them separate posts.
Just to choose 3 from 17 : use combination
To choose 3 and give separate posts: use permutation
So we have to use permutation.
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It can be done is 17P3 ways.
![{}^(17) P_3 = (17!)/((17-3)!) \\ = (17!)/(14!) \\ =17 * 16 * 15 \\ = 4080](https://img.qammunity.org/2019/formulas/mathematics/high-school/mfyrmmdhvs6dbk5hdahrihwc7qy43x31xk.png)
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From the chosen 3, you have to select 2 at random for Senate.
Choose 2 from 3.
Number of ways = 3C2 = 3! / [ 2! × (3-2)! ] = 3! / 2! = 3
You can do it in 3 ways.