Question

You want to calculate the displacement of an object thrown over a bridge. Using -10m/s^2 for acceleration due to gravity, what would be the total displacement of the object if it took 8 seconds before hitting the water?

Answer 1

given that acceleration due to gravity is a = -10 m/s^2

initial speed will be ZERO

and we need to find the displacement in t = 8 s

now we can use kinematics equation to find the displacement

`\delta y = v_y * t + (1)/(2)at^2`

now plug in all values in it

`\delta y = 0* 8 + (1)/(2)*(-10)*8^2`

`\delta y = -320 m`

so it will displace downwards by 320 m