When driver see the child standing on road his speed is 20 m/s
So here at that instant his reaction time is 0.80 s
He will cover a total distance given by product of speed and time
![d_1 = v* t](https://img.qammunity.org/2019/formulas/physics/high-school/kqz40yzx4coa26o1k9nj8emkicl5spgjt1.png)
![d_1 = 20 * 0.8](https://img.qammunity.org/2019/formulas/physics/high-school/mt85yw5qdzrgz7he6wd9ojfcnxwgx95ks7.png)
![d_1 = 16 m](https://img.qammunity.org/2019/formulas/physics/high-school/bm721w4osuqorg44dt2fjua6t1koar0etx.png)
now after this he will apply brakes with acceleration a = 7 m/s^2
so the distance covered before it stop is given by
![v_f^2 - v_i^2 = 2 a d](https://img.qammunity.org/2019/formulas/physics/college/vin3phamk8pi03gn2iad6frejb8mf9o4r4.png)
![0 - 20^2 = 2*(-7)*d_2](https://img.qammunity.org/2019/formulas/physics/high-school/rumm8zmqixuksn2qi5ypzuombfcabd7hgf.png)
![d_2 = 28.6 m](https://img.qammunity.org/2019/formulas/physics/high-school/atwu1bvo2fxdvs6im39pz2hhn7b12umfms.png)
so the total distance covered by it
![d = d_1 + d_2](https://img.qammunity.org/2019/formulas/physics/college/1c2vnfw38fhnzf8fbkx6twk089k7f7xpv0.png)
![d = 16 + 28.6 = 44.6 m](https://img.qammunity.org/2019/formulas/physics/high-school/yl2aogsjxalptghj8kaaa1uqpj28m1rg0o.png)
so it will cover a total distance of 44.6 m