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Consider the following reaction:

10 KCIO3 + 3 P4 → 3 P4010 + 10 KCI
Given 30 moles of P4 and 86 moles of KCIO3, which would act as the limiting reactant?

User Levy
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1 Answer

6 votes

Answer:
KClO_3 is the limiting reactant in the given reaction.

Step-by-step explanation:

Limiting reagent is defined as the chemical specie which gets totally consumed in the reaction and the formation of product is dependent on this reagent.

We are given:

Moles of
P_4 = 30 moles

Moles of
KClO_3 = 86 moles

The given chemical equation follows:


10KCIO_3+3P_4\rightarrow 3P_4O_(10)+10KCI

By Stoichiometry of the reaction:

If 10 moles of
KClO_3 reacts with 3 moles of
P_4

Then, 86 moles of
KClO_3 will react with =
(3)/(10)* 86=25.8moles of
P_4

As, given amount of
P_4 is more than the required amount. So, it is considered as an excess reagent.

Therefore,
KClO_3 is considered as a limiting reactant because it limits the formation of product.

User Jan Krynauw
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