Question

A bicycle rider starting with a speed (vi=0) speeds up to a speed of 8.24 m/s while traveling a distance of 42.5 meters. What is the acceleration of this rider?

Answer 1

Acceleration of the rider = 0.799
`m/s^2`

Explanation:

We have equation of motion,
`v^2=u^2+2as`, where u is the initial velocity, u is the final velocity, s is the displacement and a is the acceleration.

Initial speed of bicycle rider = 0 m/s

Final speed of bicycle rider = 8.24 m/s

Traveling distance = 42.5 meters.

Substituting

`8.24^2=0^2+2*a*42.5\\\\a=0.799m/s^2`

Acceleration of the rider = 0.799
`m/s^2`