214,287 views
30 votes
30 votes
Drag each length to the correct location on the image. Each length can be used more than once, but not all lengths will be used.

What are the missing segment lengths in the image?
12√3
24
12√2
12
45
E
45°
12
24√3 24√2
45°
45°

Drag each length to the correct location on the image. Each length can be used more-example-1
User Erigami
by
3.1k points

1 Answer

27 votes
27 votes

Answer:

DF=12√2

FG=12√2

DG=24

Explanation:

Ratio of special Right Triangle (45:45:90): x:x:x√2

Triangle DEF: x:x:x√2

x=12

12: 12: 12√2

So, DF= 12√2

Opposite (if q, then p) Base angle theorem. So, FD≅FG.

FD=12√2

FG=12√2

Ratio of 45:45:90 Triangle: x:x::x√2

x in triangle FDG= 12√2

12√2:12√2:12√2(√2)

12√2*√2=24

=12√2: 12√2: 24

DG=24

User Prabhu Murthy
by
3.1k points
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