101k views
2 votes
If density is 22.57g/cm^3 what volume would be occupied by 4.80kg of osmium

1 Answer

4 votes

Density is equal to the ratio of mass to the volume.

The mathematical expression is given as:


density=(mass)/(volume)

Arrange the above expression in terms of volume, i.e.


volume = (mass)/(density)

Density of osmium is equal to =
22.57 g/cm^(3)

Mass of osmium = 4.80 kg

First, convert the mass in kg to g:

1 kg = 1000 g

Therefore, mass in g =
4.80* 1000 = 4800 g

Put the values,


volume = (4800 g)/(22.57 g/cm^(3))

=
212.67 cm^(3).

Hence, volume occupied by osmium =
212.67 cm^(3).

User Manasov Daniel
by
8.5k points