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How do you solve 9x + 7i < 3(3x+7u)
please show you're working out! thanks in advance

User ZSprawl
by
6.0k points

1 Answer

5 votes

Let's solve for i.

9x + 7i <3 (3x+7u)

First add -9x to both sides.

7i + 9x + −9x < 21u + 9x + −9x

7i < 21u

Then Divide both sides by 7.

7i/7 < 21u/7

The answer is i < 3u

User Aderemi Dayo
by
6.4k points