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Identify the vertex, focus, and directrix of the parabola who’s equation is y^2=2x

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2 votes

y² = 2x ⇒ x =
(1)/(2) y^(2)

vertex (0, 0)

focus:
(1)/(4p) = (1)/(2) ⇒ p =
(1)/(2) so focus is: (
(1)/(2) , 0)

directrix: x =
-(1)/(2)


User Peder Klingenberg
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