96.7k views
4 votes
Determine whether the function below is an even function, an odd function, both, or neither. f(x)=x^2+3 Answers choices: A. Odd function B. Even function C. Neither even nor odd D. Both even and odd

User Jay Shukla
by
6.0k points

2 Answers

1 vote

Answer:

B. Even Function

Explanation:

I just took this test on plato and it is correct.

Even function: a function in which f(-x) = -f(x) for all values. When graphed it is symmetric about the origin. This equation meets all of the criteria for an even function.

User Roger Stewart
by
6.6k points
6 votes

The answer is: B. Even function.

The explanation for this exercise is shown below:

1. You must substitute
x with
-x in the function:


f(x)=x^(2) +3\\ f(-x)=(-x)^(2) +3\\ f(-x)=x^(2) +3

2. As you can see,
f(-x)=f(x), therefore it is an Even function.

User Stuyvenstein
by
5.9k points