Question

A ball rolls down a hill, starting from rest. How long is it rolling if it accelerates at 3m/s2 and ends with a velocity of 35m/s?

Answer 1

The answer to this question is
`11.67 s`

Step-by-step explanation

As we know that accelartion is the rate of change of velocity. So, it can be write as

`a = (V_f -V_i) /t`

where

`V_f` is the final velocity

`V_i` is the initial velocity

t is the time

a is the accelartion

as we konw

`a = 3 ms^(-2)`

t = ?

From rest So,

`V_i` = 0

`V_f = 35 ms^(-1)`

Putting values

`3 = (35 - 0)/t`

`3 = 35/t`

`t = 35/3`

`t = 11.67 s`

So, the right answe is
`11.67 s`