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Evaluate the piecewise function below for f(0):

f(x) = { 5 if x < 0
x + 3 if 0 <= x <= 4
2x - 1 if x > 4

Write answer as a single number

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Evaluate f(0)

We have 3 different function inside piecewise function

f(x) = 5 if x < 0

f(x)= x + 3 if 0 <= x <= 4

f(x) = 2x - 1 if x > 4

f(0) means we need to find f(x) when x=0

Now we check all the inequalities that satisfies x=0

0 <= x <= 4 means x = 0 to 4 but 4 is not included

x=0 satisfies the inequality 0 <= x <= 4

So we use f(x)= x + 3 to find f(0)

Replace x with 0

f(x)= x + 3

f(0)= 0 + 3 = 3

f(0) = 3

User Gaurav Jassal
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