Question

What is the radius for the circle given by the equation? (Please help gmanyp)

Answer 1

The equation of a circle:

`(x-h)^2+(y-k)^2=r^2`

where

(h, k) - the coordinates of a center

r - the radius

We have:

`(x-2)^2+y^2=14\\\\(x-2)^2+(y-0)^2=(√(14))^2`

`Answer:\ r=√(14)\approx3.742`

Answer 2

Equation of a circle is: (x - h)² + (y - k)² = r² ; where (h,k) is the center and r is radius

So, (x - 2)² + y² = 14 has a center at (2,0) and radius of √14 = 3.7416

Answer: r = 3.742