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Solve the following system of equations algebraically
3x-y=0
5x+2y=22

User Danche
by
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1 Answer

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3x - y = 0 ⇒ 2(3x - y = 0 ) ⇒ 6x - 2y = 0

5x + 2y = 22 ⇒ 1(5x + 2y = 22) ⇒ 5x + 2y = 22

11x = 22

x = 2

3x - y = 0 ⇒ 3(2) - y = 0 ⇒ 6 - y = 0 ⇒ 6 = y

Answer: x=2, y=6

User Amit Shah
by
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