Question

A company’s profits (P) are related to increases in a worker’s average pay (x) by a linear equation. If the company’s profits drop by $1,500 per month for every increase of $450 per year in the worker’s average pay, what is the slope of the graph of the equation?

pls write the ANSWER ON A GRAPH

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-Sophia G

Answer 1

Answer: Our required slope is -0.3.

Explanation:

Since we have given that

Profit is dropped by $1500.

so, amount of profit = (-)$1500

Worker's average pay is increased by $450.

Amount of average pay = (+)450

So, the slope of the graph of the equation would be

`Slope=\frac{\text{Change in average pay}}{\text{Change in price}}\\\\Slope=(+450)/(-1500)\\\\Slope=-0.3`

Hence, our required slope is -0.3.

Answer 2

company’s profits (P) are related to increases in a worker’s average pay (x) by a linear equation.

We can write this expression in the form of linear equation as

p=K x + C where C is y-intercept.

For C=0, the equation reduces to

p = K x

The company’s profits drop by $1,500 per month for every increase of $450 per year in the worker’s average pay.

Company's loss after a year=$1500 × 12 =$18,000

p = K x

(x, p) = (450, -18,000) So we will take

⇒-18,000=450 K

⇒-18,000=450 K

⇒K= -18,000/450

slope of the graph of the equation= -18,000/450

= -1800/45

K = -200/9

The equation becomes y=
`-(200)/(9)* x`