Question

The sum of 3 consecutive number multiples of 6 is 162 find thesse numbers

Answer 1

let the numbers are x , x+1 ,x+2

∴ 6 [ x + (x+1) +(x+2) ] = 162

∴ x + (x+1) + (x+2) = 162/6 = 27

∴3x + 3 = 27

∴ 3x = 27 - 3 = 24

∴ x = 24/3 = 8

So, the numbers are 8 , 9 , 10