let the numbers are x , x+1 ,x+2
∴ 6 [ x + (x+1) +(x+2) ] = 162
∴ x + (x+1) + (x+2) = 162/6 = 27
∴3x + 3 = 27
∴ 3x = 27 - 3 = 24
∴ x = 24/3 = 8
So, the numbers are 8 , 9 , 10
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