Question

You are trying to find out how high you have to pitch a water balloon in order for it to burst when it hits the ground. You discover that the balloon bursts when you have pitched it to a height of 10 m.

with what velocity did the ballon hit the ground? The acceleration of gravity is 9.8 m/s^2. The positive direction is up, to the velocity when it hits is negative. An

Answer 1

this is correct

Step-by-step explanation:

Answer 2

It is given that the balloon fell from a height of 10 m.

So, its displacement in the vertical direction h = -10 m, because the question specifically asks us to take the upward direction as +.

Acceleration in the vertical direction
`a_(y)  = -9.8 m/s^(2)`

Since the balloon dropped from a given height, its initial velocity
`V_(i) = 0`

Final Velocity
`V_(f)  = ?`

Using the equation
`V^(2) _(f)  = V^(2) _(i) + 2(a_(y) )(h)`

and plugging in the known values, we get [tex]V^{2} _{f} = 0 + 2(- 9.8)(- 10)

Solving this for [tex]V_{f}, we get [tex]V_{f} = 14 m/s or [tex]V_{f} = -14 m/s

Since the question is asking us for the final velocity, which faces downward direction, we choose [tex]V_{f} = -14m/s as the final answer.