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39 votes
39 votes
A particle P moves with constant velocity v. Initially P is at the point with position vector a. t seconds later P is at the point with position vector b. Find v when:

a= 2i + 3j, b= 6i + 13j , t = 2

User Yousaf
by
2.7k points

1 Answer

21 votes
21 votes

Answer:

correct

Explanation:

So the acute angle between the vectors is 7.122° (3sf). Explanation: The angle θ between two vectors →A and →B is related to the modulus.

User Nmclean
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3.0k points