Question

A solution is prepared by dissolving 22.7 g of CaCl2 in 375 g of water. The concentration of CaCl2 is __________% by mass.

Answer 1

The solution is 5.71 % CaCl₂ by mass.

Total mass = 22.7 g + 375 g = 397.7 g

`\%\text{CaCl}_(2) = \frac{\text{Mass of CaCl}_(2)}{\text{Total mass}}* 100 \%\\`

`\%\text{CaCl}_(2) = \frac{\text{22.7 g}}{\text{397.7 g}}* 100 \%\\`